lx^2+3x+1l=1

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Solution for lx^2+3x+1l=1 equation:


Simplifying
lx2 + 3x + 1l = 1

Reorder the terms:
1l + lx2 + 3x = 1

Solving
1l + lx2 + 3x = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-3x' to each side of the equation.
1l + lx2 + 3x + -3x = 1 + -3x

Combine like terms: 3x + -3x = 0
1l + lx2 + 0 = 1 + -3x
1l + lx2 = 1 + -3x

Reorder the terms:
-1 + 1l + lx2 + 3x = 1 + -3x + -1 + 3x

Reorder the terms:
-1 + 1l + lx2 + 3x = 1 + -1 + -3x + 3x

Combine like terms: 1 + -1 = 0
-1 + 1l + lx2 + 3x = 0 + -3x + 3x
-1 + 1l + lx2 + 3x = -3x + 3x

Combine like terms: -3x + 3x = 0
-1 + 1l + lx2 + 3x = 0

The solution to this equation could not be determined.

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